Comments on: Curved Arrows (for reactions)

By: Phill

Phill — Sat, 20 Feb 2021 10:29:06 +0000

I give this article two thumps up

By: James Ashenhurst

James Ashenhurst — Mon, 28 Oct 2019 18:13:57 +0000

In reply to Dan. Fixed. Thanks!!!

By: Dan

Dan — Sun, 27 Oct 2019 21:09:14 +0000

Another small mistake. Under your section entitled “The Three Legal Moves”, you have: “long pair → bond”. I believe this should be “lone pair”. Thanks!

By: James

James — Fri, 21 Oct 2016 01:19:33 +0000

In reply to Fitzpatrick. There is some ambiguity with pi bonds, but C1 is the best answer, since the curved arrow "head" is closer to C1 than it is to C2 and also points away from C2. If one wanted to draw the arrow connecting to C2, the way to do it would be to draw the H+ closer to H2 and have the arrow point away from C1.

By: Fitzpatrick

Fitzpatrick — Wed, 19 Oct 2016 03:06:25 +0000

For the last example, it is correct that had you not described that C1 is making the bond, that drawing a bond from either C1 or C2 to the hydrogen are both acceptable answers?

By: James

James — Mon, 14 Sep 2015 16:53:55 +0000

In reply to Harindu. Yes, this is allowed. In fact it is probably better!

By: Harindu

Harindu — Mon, 14 Sep 2015 03:19:53 +0000

Hello sir,
When lone pair to bond formation is drawn, is it ok if someone draw the arrow head in the middle of the atoms where the bond is formed?

By: Natalie

Natalie — Wed, 05 Mar 2014 16:23:24 +0000

I just wanted to give this site two thumbs up! I am currently in Orgo II and I have been struggling with mechanisms on my exams (I took Orgo I years ago and couldn’t remember how to “arrow push”). This REALLY helped a lot!! Thank you so much for taking the time to write this out :)

By: James Ashenhurst

James Ashenhurst — Wed, 06 Nov 2013 20:53:20 +0000

In reply to Selena. When H+ becomes "more negative" by 1, it goes from a charge of +1 to a charge of zero. Likewise when a neutral carbon (charge: 0) becomes more positive by 1, it goes from a charge of 0 to a charge of +1. Does that make sense?

By: Selena

Selena — Wed, 06 Nov 2013 09:13:57 +0000

hello Sir,
thank you so much for this article.It really helped me.But I didn’t understand this “Again, the atom at the “tail” (C-1) becomes more positive by 1, and the atom at the head (H+) becomes more negative by 1.” does this mean the new product formed, H should have -1 charge and C1 +1 charge?I ‘m not getting it pls help.